Build Your Own LED Turn Signals!

My brain does not like this. Thevenin and Norton are bad for me.

How about a boosted zener circuit to trickle charge a 6 volt battery.
Lead acid, Nicad, or Nimh.

Hey Spad4me,

Although I haven't had a ton of experience designing battery chargers, I think I get your drift as far as using a "boosted zener" diode - you're thinking of going the BJT route? At any rate, I'd need to see a schematic of exactly what you're thinking, but whatever you end up with, you need to be sure that the applied voltage/current output of the charger tapers off as the battery recharges. Batteries have optimal "quick charge" and "floating" voltages, so I'd be sure to take a look at those for whichever battery you decide to go with. I'd actually point you toward this SLA charger design. Although I haven't done this build personally, the author takes a lot of good things into consideration, and I'd bet you'd do just fine following that lead. Good luck!
 
like a rock, after reading this about 3 times, im still pretty much clueless lol. my biggest question---in that diagram, that is a circuit board right? and i know you took tons of time to write this, but would it be possible to do a 1st hook this thingy ma bobber to this doohickey ect ect so peeps like me that are clueless can figure it out? thanks. if this is not possible i found a set, but it would cost 40 bucks for front and rear lights.... and i gotta do this on 2 bikes.


oh, and aug.. if i could figre this out, i would be MORE than happy to make kits, but i would need to figure how to do it 1st :)

Hey eltatertoto!

That's an excellent question about the diagram. If by circuit board, you mean something like this, then the answer is yes... sort of. :) Actually, it's kind of a mix between what the circuit components would look like from an "aerial view" on a real-life circuit board (the CD4047BE) and the circuit symbols that are commonly used to depict circuit devices on paper (the resistor as a squiggly line, the capacitor, the LEDs as triangles with a line, the DPDT switches, etc.). Think of this diagram more as just an on-paper representation of the circuit, not as an actual depiction of what the circuit board would look like. In fact, when I did this, I didn't even use a green circuit board - just wire and solder.

As for the step-by-step description, I can definitely do that. I won't have time to do it tonight, but I should be able to get to it this week. Hopefully that will help in understanding exactly what needs to be done.

Glad you asked!
 
Hey eltatertoto!



As for the step-by-step description, I can definitely do that. I won't have time to do it tonight, but I should be able to get to it this week. Hopefully that will help in understanding exactly what needs to be done.

Glad you asked!

thanks, and i already am getting a battery like that one for my radio project. but if i send kits, i dont think its legal to ship lead acid batteries. what with all the terrorist carp. so if i make kits yous guys will have to buy yr own batts. but i might make options as to what box you want and such. i might even mount the board near the battery, and use 2 boxes so you wont have a huge box on yer bars. but i think ill wait till ya get the step by step up, cause i dont want to bother my dad, its just starting to warm up and my dad is on his vacation, and hes trying his dangest to get the harleys ready, within his 10 day vacation. he bought tons of new stuff over thhe winter.
 
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Step-by-step instructions

Here are step-by-step instructions on how to make the 12V LED turn signal setup described in the first post. These instructions aren't designed for understanding the circuit; they're really just for helping people put the pieces together properly. Let me know if you have questions.

1. Go buy:

- 2x 12V LED modules of your choice. (don't get too crazy here - the circuit is designed for a generic LED setup, not a 4,000,000-lumen LED searchlight...)
- 2x RFD3055LE N-channel Mosfets from Digikey.com. (0.79 USD each) -datasheet here-
- 1x CD4047BE Multivibrator from Digikey.com. (0.48 USD each) -datasheet here-
- 2x DPDT switches of your choice (what you'll be switching to turn on and off the turn signals). Radioshack is a good bet. They can be bought from Digikey, but I like to see/feel a switch before I buy it.
- 1x 100uF electrolytic capacitor - go to RadioShack, or tack one onto your Digikey order
- 1x 2-3 kOhm trimpot/potentiometer/variable resistor/whatever else you'd like to call it. Nothing fancy here. I'd get one for $0.50 at Radioshack. Will probably have 3 pins, but might have only 2.

ORDER EXTRAS - THEY'RE CHEAP! If you've never soldered to integrated circuits before, you should definitely buy extras. Prolonged exposure to the soldering iron's heat can damage them, so be careful!

2. Solder pins 4, 5, 6, and 14 of your CD4047BE together (see diagrams), and solder a wire coming off of one of these pins. These pins will all be connected to +12 V eventually. Check for continuity of these connections using a multimeter in resistance-measuring mode. Put one multimeter probe on the free end of the wire, and move the other probe from pin to pin. The resistance measurements should be 0 ohms or very small (<<10 ohms).

3. Solder pins 7, 8, 9,and 12 of your CD4047BE together, and solder a wire coming off one of these pins. These pins will all be connected to 0 V (GND, the negative side of the battery) eventually. Again, check for continuity of these connections with a multimeter.

4. Determine the pinout of your trimpot/potentiometer/etc. Basically, you need to use your multimeter to identify two pins (normally of three pins total) between which the resistance changes when you twist the knob. Normally this is the middle pin and either of the two outer pins. By spinning the knob, you should be able to change the resistance you're measuring from ~0 ohms to the max for your potentiometer (probably 2-3 kOhms).

5. Solder one of these two pins on the potentiometer (you identified these in the previous step) to pin 2 on the CD4047BE, and solder the other pin to pin 3 on the CD4047BE. You may want to use wire for this, you may not.

6. Identify which one of the two pins on your 100 uF capacitor is the positive pin. If you didn't buy an electrolytic capacitor, don't worry about this step. If you did buy an electrolytic capacitor, one of your capacitor's lead wires is probably longer than the other one. This is the POSITIVE one. Also, there may be markings on the plastic wrapper of your capacitor indicating the lead polarity. In my original schematic (from the first post), you will notice that half of the capacitor is shown as curved, while half of the capacitor is shown as straight. The curved side of the capacitor is the negative side, and the flat side of the capacitor is the positive side.

7. Solder the POSITIVE lead of the capacitor to pin 3 of the CD4047BE, and solder the NEGATIVE lead of the capacitor to pin 1. You will note that your potentiometer is also soldered to pin 3 (step 5). Try not to damage the solder connection you already made.

8. Make sure you know which pins are what on your two Mosfets. These are labeled with "S" (source), "D" (drain), and "G" (gate) in the images I attached to this post.

9. Using wire, solder the G pin on each of the Mosfets to pin 10 on your CD4047BE.

10. Using wire, solder the S pin on each of the Mosfets to the connection you made earlier between pins 7, 8, 9, and 12 on your CD4047BE (step 3).

11. Solder the negative wire of one of your LED modules to the D pin (middle pin) of one of the Mosfets. Also do this for the other LED module and the other Mosfet.

12. Use a multimeter in resistance-measuring mode to determine the operation of the six pins on each of your DPDT switches. You really need to understand how a DPDT switch works in order to do this. In general, the two middle pins are the throws, and the four outer pins are the poles. If you're having trouble with this part, post a question.

For each of the two switches:

- Throw #1 should be soldered to ground.
- Throw #2 should be connected to +12 V on the battery.
- When the switch is in position A (arbitrarily assigned), throw #1 should be connected to pin D of one of the Mosfets. Throw #2 should be connected to nothing.
- When the switch is in position B (the OTHER position :)), throw #1 should be connected to nothing. Throw #2 should be connected to the connections you made between pins 4, 5, 6, and 14 on your CD4047BE (step 2).

13. Finally, connect the positive wire of your LED module to +12V on the battery.

-- I almost forgot to mention that if your turn signals are flashing really quickly or really slowly, you need to twist the knob on the potentiometer until they flash at a speed you like.

-- Also, as an optional suggestion, I usually cover the small, fragile connections between components in a hefty layer of hot glue when I'm done. It protects the solder joints both from shorting to other metal objects and breaking under stress. Just be sure your circuit is working before you do this :).


All of these connections should be identical to what is drawn in the original schematic, so if you're having trouble conceptualizing what it should look like, head there.

Good luck!

-Rock
(sorry I picked such a long name when I joined... "Rock" is much easier to type, lol.)
 

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rock, thanks a bunch for doing this.... i will read once the fumes leave my head lool, i just patched a tank, in a shed, and i wasnt about to open the door cause i had the heater on..... soo once my fume induced headache goes away ill read it. i have been out there since noon doing various things,... and it is 950 now :eek: wow! 950, it jhust hit me how late it is as i typed that! holy carp! 10 hrs ive been in that danged shed! wow i need to get a clock out there. sorry about side trailing.



EDIT: rock, i just read it and i find it VERY easy to understand, and now, after reading it, i am confident it is possible. i just gotta get a soldering iron and a multimeter. all i have now is a carpy cold heat p.o.s. melts solder my azz!

i have had experience soldering. i used my dads iron to make this little circuit board starter kit that in the end made a fan blow and an led blinked. to learn to solder (he wanted me to learn so i would know how to do stuff like this)

oh, and congrats on becoming a member, and not a jr.member rock!
 
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Excellent! And I totally agree with you about those "cold-heat" gizmos. Definite carp, plus the current used to heat the tip can accidentally fry your circuits.:-/
 
oh! rock, i almost forgot. if i were to hook up front ones also, i would just splice into the led lights' wires, after all is wired and hookes up, right? thanks.
 
i will be buying everything tommrow. i will buy 5 of everything (except batterys), and 7 of the multi thingy so i will have 3 kits ready to go from the get-go. (mabey 2 depending on if i hook one up to my racing bike.) but i definately will not be making these in bulk til i get orders. i dont wanna waste my money (or what little i have) but if i get a system going, i promise ill be making lots of kits in the future.
 
oh! rock, i almost forgot. if i were to hook up front ones also, i would just splice into the led lights' wires, after all is wired and hookes up, right? thanks.

Right. Instead of having one LED module going from +12V to the D pin on each Mosfet, you would have two LED modules going from +12V to the D pin on each Mosfet, in parallel. The only thing this now introduces into the situation is twice the current going through each Mosfet ("continuous drain current", labeled Id). I picked these Mosfets out for a good balance between better-than-needed properties and low cost, and they can handle an Id of up to 11 amps. Each LED module should draw about 60-80 mA of current, so you should be around just 2% of max.

Keep us all updated with your progress - I'm interested to see what you think of the circuit!

PS - don't forget to buy 10 Mosfets!
 
thanks again rock! it wazs a silly question, but i wanted to make SURE. i might even wire an led into the board for each switch, so i know when the lights are on.
 
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