Ollie
Member
Hello all, I'm switching to 24" wheels because I have a really strong set from a dirt jump bike that I want to use. My more maths-literate friend has made an equation to calculate what size rear sprocket will be required:
(pi x [radius of smaller wheel]^2)/(pi x [radius of larger wheel]^2) = [ratio]
[no. of teeth on original sprocket] x [ratio] = [no. of teeth on new sprocket]
Example:
24" x 24" = 576
3.14159265359 x 576 = 1809.55737
26" x 26" = 676
3.14159265359 x 676 = 2123.71663
1809.55737 / 2123.71663 = 0.85207101
44t x 0.85207101 = 37.4911244 (dunno if you can find a 37t sprocket, so round down to a 36t or up to 38t)
Hope y'all find it useful!
(pi x [radius of smaller wheel]^2)/(pi x [radius of larger wheel]^2) = [ratio]
[no. of teeth on original sprocket] x [ratio] = [no. of teeth on new sprocket]
Example:
24" x 24" = 576
3.14159265359 x 576 = 1809.55737
26" x 26" = 676
3.14159265359 x 676 = 2123.71663
1809.55737 / 2123.71663 = 0.85207101
44t x 0.85207101 = 37.4911244 (dunno if you can find a 37t sprocket, so round down to a 36t or up to 38t)
Hope y'all find it useful!