Otto Neumann
Active Member
Assuming a total RPM of 5k, as my preference is rolling to a gentle pace:(RPM × Wheel Diameter × π)
÷ (1056 × Total Reduction)
= MPH
Those two engines max hp rpm is 6800.
If you aren't very good at figuring up Total Reduction, use this formula. Teeth pulleys and sprocket can be interchangeable
(RPM × Wheel Diameter × π × Drive Sprocket(s)T)
÷ (1056 × Driven Sprocket(s)T)
= MPH
(5000 x 26 x 3,14 x 28) / (1056 x144)
11429600 / 152064 = 75 mph
*Wheeeze* Oh wow, that's quite fast for a 53cc, something feels off

After fiddling around a little, I came across an unnoticed issue, I believe you saved my bacon:
I double checked my math document, apparently I had calculated my ratios with a 144T pulley, planned to be machined, instead of the 122T that I currently have assembled on the bike; everything was off.
I recalculated everything, and I placed, as comparison, the equivalent 415 chain sprocket pairing.
- HTD-5M belt to 415 chain -
15T-122T = 8,13:1 (10T- 81T)
20T-122T = 6:1 (10T-60T)
24T-122T = 5:1 (10T-50T)
25T-122T = 4,88:1 (10T-48T)
27T-122T = 4,52:1 (10T-45T)
28T-122T = 4:36:1 (10T-43T)
30T-122T = 4:1 (10T-40T)
32T-122T = 3,8:1 (10T-38T)
I have a 28T drive pulley, so it's gonna behave like when I was running a 43T sprocket, which NGL was a good compromise between torque and speed; oh well, at least the mistake didn't turned my bike any worse
