Who can do math

Most engine side sprockets are 10 tooth. Gear clutch reduction of most new engines is 4.1:1. Your chain drive to the rear wheel is a 3.2:1 reduction. 4.1 x 3.2 = 13.12:1 total gear reduction.

Now you can translate engine rpm to rear axle rpm by dividing the engine rpm by the total gear reduction.

8101/13.13= 617.45 Rpm

From here you need to calculate the tire circumference. Multiply that times the number of revolutions per minute. This will give you a distance covered every minute. From there you just need to do the math to convert whatever distance for every minute into miles per hour. 😉
 
 
Speed is 47.8 if that’s what you’re looking for…
On a 10T countersprocket
 

Attachments

  • 666FDF1A-C4A5-45C8-8A25-093E9B5A8B6A.jpeg
    666FDF1A-C4A5-45C8-8A25-093E9B5A8B6A.jpeg
    89.1 KB · Views: 33
(RPM × Wheel Diameter × π)÷(1056 × Total Reduction) = MPH

Engine reduction x Drive reduction = Total Reduction

(82÷20)×(32÷10)=13.12

(8,101×26×π)
÷(1,056×13.12)
=47.7599759688 mph
 
YO pilgrims! Is the wheel diameter 26" including the tire? That is the ?. I say it doesn't so stated math is incorrect. Tires also are different from tire to tire. Air pressure and weight depressing the tire must also be considered to accurately calculate speed.
 
YO pilgrims! Is the wheel diameter 26" including the tire? That is the ?. I say it doesn't so stated math is incorrect. Tires also are different from tire to tire. Air pressure and weight depressing the tire must also be considered to accurately calculate speed.
My Kendra 838's is 26.25" when fully inflated in my top gear at 7000 rpm the difference in speed between 26" and 26.25" is only about 1/3 mph. So the difference is not significant enough to really matter.
 
Back
Top