loquin
Well-Known Member
A wider tire CAN safely run at lower pressures than a narrower tire, because the area of the tire in contact with the ground is greater than with a narrow tire at the same deflection. Since the pressure is in pounds per square inch (in the US,) IF you increase the area (in square inches,) you can proportionally decrease the pressure to support the same weight, or increase the weight supported at the same pressure.
The sketch below is a diagram of this effect. A downwards force F deflects a tire where it contacts the ground. The contact area for a tire, and a tire which is twice as wide, are both shown.
The contact area of the tire is equal to the downwards force, divided by the tire pressure. If a tire supports 100 pounds, and the tire pressure is 50 PSI, the contact area would equal 100 / 50, or 2 square inches. A 2 inch wide tire would have 1 inch of it's circumference (average) in contact with the ground. A 4 inch wide tire at the same pressure would only have a half inch of the circumference in contact. For the same deflection of the sidewalls, you could cut the tire pressure in half, to 25 PSI. You would then have 4 square inches of the tire in contact, but, since the tire is 4 inches wide, you would have 1 inch of the circumference in contact...
This is also why narrow tires HAVE to run at high pressures, in order to support the rider's weight.
However, this does not justify underinflating a tire, as the extra flex in the sidewalls can cause a LOT of stress in the sidewall near the rim, especially with today's narrower rims.
The sketch below is a diagram of this effect. A downwards force F deflects a tire where it contacts the ground. The contact area for a tire, and a tire which is twice as wide, are both shown.
The contact area of the tire is equal to the downwards force, divided by the tire pressure. If a tire supports 100 pounds, and the tire pressure is 50 PSI, the contact area would equal 100 / 50, or 2 square inches. A 2 inch wide tire would have 1 inch of it's circumference (average) in contact with the ground. A 4 inch wide tire at the same pressure would only have a half inch of the circumference in contact. For the same deflection of the sidewalls, you could cut the tire pressure in half, to 25 PSI. You would then have 4 square inches of the tire in contact, but, since the tire is 4 inches wide, you would have 1 inch of the circumference in contact...
This is also why narrow tires HAVE to run at high pressures, in order to support the rider's weight.
However, this does not justify underinflating a tire, as the extra flex in the sidewalls can cause a LOT of stress in the sidewall near the rim, especially with today's narrower rims.
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